7-6x+18+8x-40=3^2-x

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Solution for 7-6x+18+8x-40=3^2-x equation: 



7-6x+18+8x-40=3^2-x

We move all terms to the left:

7-6x+18+8x-40-(3^2-x)=0

We add all the numbers together, and all the variables

2x-(3^2-x)-15=0

We get rid of parentheses

2x+x-15-3^2=0

We add all the numbers together, and all the variables

3x-24=0

We move all terms containing x to the left, all other terms to the right

3x=24

x=24/3

x=8

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